Alphabet series Completion-Verbal Reasoning

KSU

because, first letter follow the pattern of +3

second letter follow the pattern of +2

third letter follow the pattern of +2

that is, H+3=K

Q+2=S

S+2=U

hence KSU is right answer.

D

here, letters follow the pattern of +7.

that is,

U+7=B

B+7=I

I+7=P

P+7=W

W+7=D

hence D is right answer.

first option is correct.

W, Q, K, E

this seqence follows the pattern of -3

e,j

This sequence follows the pattern of

a+3=d, d-1=c, c+3=f, f-1=e, e+3=h, h-1=g, g+3=j, j-1=i

hence correct answer is e, j.

option 1 is correct

MNOP

Each term consists of consecutive letters in order.

Also, there is a gap of one letter between the last letter of the first term and first letter of the second term, there is a gap of two letter between the last letter of the second term and first letter of the third term, Hence  there must be a gap of three letter between the last letter of the third term and first letter of the fourth term, that is MNOP,

in this way there is a gap of four letter between the last letter of the first term and first letter of the fifth term, hence correct answer is MNOP.      

B

We have 3 patterns.

pattern I =  A B C D .....X Y Z, which occurs only once and has 26 letters.

pattern II =  Y X ......B A, which repeats alternately and has 25 letters.

pattern III = B C D......Y Z, which repeats alternately and has 25 letters.

number of letters before desired term = 999-26=973

each patterns which occurs after pattern I has 25 letters.

973 ÷25 gives quotient=38 and remainder is 23.

Thus 1000th term of the given series is 24th term of the 39th pattern after I.

Clearly, the 39th pattern is II and its 24th term is B.

L11T

The first letters in odd numbered terms form series,  J-1=I, I-1=H,

The first letters in even numbered terms form series, K+1=L, L+1=M

Middle number form the series,

2+2=4,

4+3=7

7+4=11

11+5=16

16+6=22

the third letters of the each terms form series,

Z-2=X, X-2=V, V-2=T, T-2=R, R-2=P

Hence the required term is L11T.

andaa

the pattern 'abadna' is repeated.

bbaab

the pattern 'baab' is followed.

acab

the pattern bcaa is followed.

adabcd

the series is acdb/dacb/cdab/acdb/da. The third letter in each sequence becomes the first letter in the following sequence.